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Old 08-04-2010, 05:08 PM   #19
Ropetow
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Quote:
Originally Posted by Resident 2B View Post
Just trying to help here. It is length (in feet) times beam (in feet) divided by 15

R2B
Thanks, R2B. I was just struggling with that one....length (20 feet) plus beam (8 feet) = 28 / 15 = a capacity of 2?

Other than when the in-laws visit, that would be a problematic formula.
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