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Old 02-05-2016, 04:37 PM   #1
HellRaZoR004
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Quote:
Originally Posted by Cobalt 25 View Post
68 but binary challenged.

How do you get 44 from 00101100?

IS that the binary system?

Peter
Yes, converting binary to decimal. This...

00101100 (0+0+32+0+8+4+0+0), corresponding to the location of each 1/0.
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Old 02-08-2016, 09:43 PM   #2
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Please explain how you get 32 for the first 1?
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Old 02-08-2016, 11:11 PM   #3
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Originally Posted by HellRaZoR004 View Post
Yes, converting binary to decimal. This...

00101100 (0+0+32+0+8+4+0+0), corresponding to the location of each 1/0.
In the following order you count the decimal equivalent of a binary number.

[128 64 32 16 8 4 2 1], if there is a '1' present in the corresponding location that number is added. If a '0' is present in the corresponding location that number is not added.

Therefore [128 64 32 16 8 4 2 1] = [0+0+32+0+8+4+0+0] = [44]

Last edited by HellRaZoR004; 02-08-2016 at 11:12 PM. Reason: Clarification
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Old 02-09-2016, 05:23 PM   #4
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Old 02-09-2016, 07:49 PM   #5
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Thanks, Hellra. An excellent explanation. Even I could understand!
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Old 02-09-2016, 09:49 PM   #6
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You're welcome Cobalt, glad it was helpful.
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